Question

log1/2(4x-1)-log1/2(8-3x)=2

Answer 1

$log_{1/2}(4x-1) - log_{1/2}(8 - 3x)=2\ log_{1/2}( frac{4x-1}{8 - 3x} )=log_{1/2}(1/4) \ frac{4x-1}{8 - 3x}= frac{1}{4} \ (4x-1)4 = 8 - 3x \ 16x - 4=8 - 3x \ 16x +3x=8 +4 \ 16x +3x=8 +4 \ 19x=12 \ x= frac{12}{19}$
Делаем проверку....

Ответ: 12/19.