Question

$Log_{4}x-log_{12}x=log_{12}27$

Answer 1

Log4x-Log12x=log12^27 перейдем к новому основанию 1.(1/logx4)-(1/logx12)=log12^27 2)logx12/logx4=log12^27. 3) logx8=log12^27 4) 3logx2=3log12^3 5). Logx2=log12^3 6). Log12^3= 1728. 7) logx2-logx^1728=0 8) logx^(2/1728)=0. 9) logx^1/864=0 . 10) x=1/864

Answer 2

Да