Question

решите систему неравенств x^2+y^2=16 x+y=-2

Answer 1

$left { {{ x^{2} + y^{2}=16 } atop {x=-2-y}} right. \ left { {{ (-2-y)^{2} + y^{2}=16 } atop {x=-2-y}} right. \ left { {{ y^{2}+4+4y + y^{2}=16 } atop {x=-2-y}} right. \ left { {{2 y^{2} +4y-12=0} atop {x=-2-y}} right. \ left { {{ y^{2} +2y-6=0} atop {x=-2-y}} right. \ D=4+24=28 \ y_{1} = frac{-2+2 sqrt{7} }{2} =-1+sqrt{7}; x_{1} =-2-(-1+sqrt{7})=-1-sqrt{7} \ y_{2} = frac{-2-2sqrt{7}}{2} =-1-sqrt{7}; x_{2} =-1+sqrt{7}$