Question

Ктонибуть ПОЖАЛУЙСТА помогите!!!!!

Answer 1

1.  $6/(2sqrt{3}-3) - 4/(sqrt{3}-1) -6/sqrt{3}$=

=  $6( <var>2sqrt{3}+3)</var> /(12-9) - 4 <var>(sqrt{3}-1)</var>/(3-1) -6</var> <var>sqrt{3}</var> <var>/3$=

= $4 <var><var>sqrt{3}</var></var> + 6 - 2 <var><var>sqrt{3}</var></var> + 2 - 2 <var><var>sqrt{3}</var></var>$=

= 8 

 

2. 1/(a-b)*(1/b^2-1/a^2)=

= 1/(a-b)*(1/b-1/a)(1/b+1/a)=

= 1/(a-b)*((a-b)/ab)((a+b)/ab)=

= (a+b)/(ab)^2

 

3. $1/(x(x-1) + (x/( (sqrt{x}-1)( sqrt{x}+1))-sqrt{x}/( sqrt{x}+1 ))/ (sqrt{x^3}/ (x-1)$ =

=  $1/(x(x-1) + ( (x - x + 1 )/( (sqrt{x}-1)( sqrt{x}+1) )/(sqrt{x^3}/ (x-1)$ = 

=  $1/(x(x-1) +(x-1)/(x(x-1)) = (x-1+1)/(x(x-1))=1/(x-1)$