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Ответ дал:
0
(2x-6)/(2x-1)>0
x=3 x=1/2
x<1/2 U x>3
(2x-6)/(2x-1)>1
(2x-6-2x+1)>0
-5/(2x-1)>0
2x-1<0
x<1/2
x∈(-∞;1/2)
x=3 x=1/2
x<1/2 U x>3
(2x-6)/(2x-1)>1
(2x-6-2x+1)>0
-5/(2x-1)>0
2x-1<0
x<1/2
x∈(-∞;1/2)
Ответ дал:
0
ОДЗ: ![frac{2x-6}{2x-1}>0 <=> (2x-6)(2x-1)>0 \ 4(x-3)(x-0,5)>0 frac{2x-6}{2x-1}>0 <=> (2x-6)(2x-1)>0 \ 4(x-3)(x-0,5)>0](https://tex.z-dn.net/?f=frac%7B2x-6%7D%7B2x-1%7D%26gt%3B0+%26lt%3B%3D%26gt%3B+%282x-6%29%282x-1%29%26gt%3B0+%5C+4%28x-3%29%28x-0%2C5%29%26gt%3B0)
x∈(
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![log_7frac{2x-6}{2x-1}>0 \ frac{2x-6}{2x-1}>7^0 \ \ frac{2x-6}{2x-1}>1 \ \ frac{2x-6}{2x-1}-1>0 \ \ frac{2x-6-(2x-1)}{2x-1}>0 \ \ frac{2x-6-2x+1}{2x-1}>0 \ \ -frac{5}{2x-1}>0 \ \ frac{5}{2x-1}<0 \ \ 2x-1<0 \ 2x<1 \ x<0,5 log_7frac{2x-6}{2x-1}>0 \ frac{2x-6}{2x-1}>7^0 \ \ frac{2x-6}{2x-1}>1 \ \ frac{2x-6}{2x-1}-1>0 \ \ frac{2x-6-(2x-1)}{2x-1}>0 \ \ frac{2x-6-2x+1}{2x-1}>0 \ \ -frac{5}{2x-1}>0 \ \ frac{5}{2x-1}<0 \ \ 2x-1<0 \ 2x<1 \ x<0,5](https://tex.z-dn.net/?f=log_7frac%7B2x-6%7D%7B2x-1%7D%26gt%3B0+%5C++frac%7B2x-6%7D%7B2x-1%7D%26gt%3B7%5E0+%5C++%5C++frac%7B2x-6%7D%7B2x-1%7D%26gt%3B1+%5C++%5C++frac%7B2x-6%7D%7B2x-1%7D-1%26gt%3B0+%5C++%5C++frac%7B2x-6-%282x-1%29%7D%7B2x-1%7D%26gt%3B0+%5C++%5C+frac%7B2x-6-2x%2B1%7D%7B2x-1%7D%26gt%3B0+%5C++%5C+-frac%7B5%7D%7B2x-1%7D%26gt%3B0+%5C++%5C+frac%7B5%7D%7B2x-1%7D%26lt%3B0+%5C++%5C+2x-1%26lt%3B0+%5C+2x%26lt%3B1+%5C+x%26lt%3B0%2C5)
x∈(
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x∈(
x∈(
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