Question

4y*(y+4)-(2y+5)*(2y-5)=-7
Решите уравнение срочно !!)

Answer 1

4y*(y+4)-(2y+5)*(2y-5)=-7
4*y^2+16*y-(4*y^2-25)=-7
4y^2+16y-4y^2+25+7=0
16y+32=0
16y=-32
y=-32/16
y= -2

Answer 2

4y*(y+4)-(2y+5)*(2y-5)=-7
16y+25=-7 | (-25)
16y=-32  | (:16)
Ответ: y = -2