Question

реши уравнения
6(2-t)=2(7-2t)-28
4(x+3)-5(2x+1)=10

Answer 1

6(2-t)=2(7-2t)-28
12-6t=14-4t-28
-6t+4t=14-28-12
-2t=-16
t=8

4(x+3)-5(2x+1)=10
4x+12-10x-5=10
-6x=3
x=-0.5