Question

Разложите на множители (b-4)^2-(a+3)^2

Answer 1

(b-4)^2 - (a+3)^2 = (b^2 - 8b + 16) - (a^2 + 6a+9) = b^2 - 8b + 16 - a^2 - 6a - 9 =
b^2 - 8b - a^2 - 6a + 7 

Answer 2

$(b-4)^2-(a+3)^2=(b-4+a+3)(b-4-a-3)=\=(b+a-1)(b-a-7)$