Question

Найдите корни уравнения:
а) (2х-1) (х+5) - (х+1) (х+2) = 0
б) (3х+1) (3х-1) = 8х - 2

Answer 1

Вот так.........................

Answer 2

1)
2x^2+10x-x-5-x^2-2x-x-2=0
2x^2-x^2+10x-x-2x-x-5-2=0
x^2-6x-7=0
D=(-6)^2-4*1*(-7)=36+28=64
x1=(6+8)/2*1=7
x2=(6-8)/2*1=-1
2) 9x^2-3x+3x-1-8x+2=0
9x^2-8x+1=0
D=(-8)-4*9*1=64-36=28
x1=8+5.3/2*9=13.3/18
x2=8-5.3/2*9=2.7/18