Question

помогите решить систему уравнений
(10а+b)-(a+b)=18
(10a+b)² - a²=480

Answer 1

$left { {{(10a+b)-(a+b)=18} atop {(10a+b)^2 - a^2=480}} right. to left { {{10a+b-a-b=18} atop {100a^2+20ab+b^2-a^2=480}} right. to left { {{9a=18} atop {99a^2+20ab+b^2=480}} right. \ left { {{a=2} atop {99cdot 2^2+20cdot2cdot b+b^2=480}} right. \ b^2+40b-84=0$
По т. Виета
 b1=-42
b2=2

Ответ: $(2;-42),,,(2;2).$