Question

3x^4-13x^2+4=0
Помогите пожалуйста

Answer 1

$3 x^{4} -13 x^{2} +4=0 \ y= x^{2} \ 3y^{2} -13y+4=0 \ D=169-4*4*3=121 \ y_{1}= frac{13-11}{6} = frac{1}{3} \ y_{2}= frac{13+11}{6} = 4 \ x^{2} =4 \ x_{1}=2\ x_{2}=-2 \ x^{2} = frac{1}{3} x_{3}= frac{ sqrt{3} }{3} \ x_{4}= -frac{ sqrt{3} }{3}$