Question

x-y=1
x2-y=3 помогите решить систему уравнений !

Answer 1

$left { {{x-y=1} atop { x^{2} -y=3}} right. \ x=1+y \ (1+y)^{2}-y=3 \ 1+2y+y^{2} -y-3=0 \ y^{2}+y-2=0 \ D=1+8=9=3^{2} \ y1=(-1+3)/2=1 \ y2=(-1-3)/2=-2 \ x1=1+y1=1+1=2 \ x2=1+y2=1- 2=-1 \ Otvet:(2;1);(-1;-2)$