Question

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Answer 1

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Answer 2

Часть  С 9)  1)  [(b0,5 + 3)2  - (b0,5  - 3)2 ] /  [b*[(b0,5 + 3)  * (b0,5  - 3) ] = [b + 6b0,5 + 3 - b + 6b0,5 – 3] / b*(b – 9) = = 12b0,5 / b*(b – 9) = 12/√b(b – 9) 2)  [12/b0,5(b – 9)] * (b – 9)/b0,5 = 12 / b   10)  √(9x2 – 6x + 1) = x2  + 1 (√(9x2 – 6x + 1) )2 = (x2  + 1)2 9x2 – 6x + 1 = x4 + 2x2  + 1 x4 - 7x2  + 6x = 0 x(x3 – 7x + 6) = 0 x1 = 0 x3 – 7x + 6 = 0 x2 = 1   x3  – 7x    + 6                                  Ix - 1
-(x3 – x2)                                             x2 + x - 6
          x2 – 7x
        -(x2 – x)
                 - 6x + 6
                -(-6x + 6)
                           0 x3 – 7x + 6 = ( x – 1)( x2 + x – 6)      x2 + x – 6 = 0 x4 = 2 Ответ:         x1 = 0; x2 = 1; x3 = - 3; x4 = 2    

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