Question

tg³x+tg²x-3tgx-3=0

Answer 1

tg²x(tg x+1)-3(tgx+1)=0

(tg²x-3)(tgx+1)=0

tgx=±√3 x=π/3+πn x=-π/3+πn

tgx=-1 x=-π/4+πn

Ответ: х=±π/3+πn и -π/4+πn