Question

(x+4)(x-7)+(x+3)(10-x) при x=0,75

Answer 1

x2-7x+4x-28-x2+10x+30-3x=4x+2=5

Answer 2

пасиб

Answer 3

(х+4)(х-7)+(х+3)(10-х)=2х-7х+4х-28+10х-2х+30-3х= 14х-10х+28=4х+28
прих=0,75, то 4*0,75+28=3+28=31