Question

решите уравнение:

(9x^4)^5*(3x)^3 / (27x^5)^4

Answer 1

(9x^4)^5*(3x)^3 / (27x^5)^4 = $frac{(9x^{4})^{5}*3x^{3}}{(27x^{5})^{4}} = frac{9x^{20}*3x^{3}}{27 x^{20}} = frac{3x^{20}*3x^{20}3x^{3}}{3x^{20}3x^{20}3x^{20}}= 3x^{3-20} = 3x^{-17} = (frac{1}{3}x)^{17}$

Answer 2

$frac{(9x^4)^5*(3x)^3}{(27x^5)^4}=frac{(3^{10}x^{20})*(3^3x^3)}{3^{12}x^{20}}=3^{10+3-12}*x^{20+3-20}=3x^3$