Question

arcsin (-1/2)
arccos корень из 2/2
arctg (-1)
arcctg1/корень из 3

Answer 1

sin(-1/2)=$pi$/6
cos($sqrt{2}$/2=$pi$/4 или cos($sqrt{2}$/2 = 7$pi$/4
ctg(-1)=cos(-1)/sin(-1)=$pi$/($pi$/2= 2
ctg$sqrt{3}$=cos$sqrt{3}$/sin$sqrt{3}$