Question

tg(2x+π/6)≥-√3 решите даю 20 баллов

Answer 1

tg(2x+π/6)≥-√3
-π/3+πn ≤ 2x+π/6 < π/2+πn, n∈Z
-π/3-π/6+πn ≤ 2x < π/2-π/6+πn, n∈Z
-π/2+πn ≤ 2x < π/3+πn, n∈Z
-π/4+πn/2 ≤ x < π/6 +πn, n∈Z
x∈[-π/4+πn/2 ; π/6 +πn),  n∈Z