Question

pomagite rewitj ja vas o4enj prowu zaranije sposibo!

Answer 1

$log_{ frac{1}{7}}(2x-1)>-1 \ log_{ frac{1}{7}}(2x-1)>-1cdot log_{ frac{1}{7}} frac{1}{7}$
$log_{ frac{1}{7}}(2x-1)>log_{ frac{1}{7}} frac{1}{7} ^{-1} \ log_{ frac{1}{7}}(2x-1)>log_{ frac{1}{7}} 7$
$left { {{2x-1>0} atop {2x-1<7}} right. \ left { {{2x>1} atop {2x<8}} right. \ left { {{x> frac{1}{2} } atop {x<4}} right.$
Ответ (1/2 ; 4)
$frac{7-4x}{x-8} leq 0$
7-4x=0      x= 7/4=2,75
x-8≠0        x≠8
                       \\\\\\\\\
--------------[2,75]-------------(8)------------
Ответ. [2,75; 8)