Question

помогите,пожалуйста :) :) :)

Answer 1

$frac{x^2}{x^2-3xy}: frac{x}{x^2-9y^2} = frac{x^2*(x^2-9y^2)}{(x^2-3xy)*x} = frac{x^2*((x-3y)(x+3y))}{x^2*(x-3y)} = x+3y \ Tak~ kak~x=5+3 sqrt{6} ,~y=2- sqrt{6}, ~to \ 5+3 sqrt{6} +3(2- sqrt{6} )=5+3 sqrt{6} +6-3 sqrt{6}=11$