Question

2у(в 3 степени)-8у  решение

Answer 1

2y(y^2-4)=0; 

2y(y-4)(y+4)=0;

y=-2; 

y=0;

y=2

Answer 2

$2y^{3}-8y=2(y^{3}-4y)=2(y(y^{2}-4))=2y(y-2)(y+2)$