Question

ПОМОГИТЕ! СРОЧНО! 238 под (б)

Answer 1

$f(x)=tg(x^2+ frac{ pi }{6} ) \ f'(x)= cfrac{1}{cos^2(x^2+ frac{ pi }{6} )} cdot (x^2+ frac{ pi }{6} )'= cfrac{2x}{cos^2(x^2+ frac{ pi }{6} )} \ f'(x_0)= f'(0)= cfrac{2cdot0}{cos^2(0^2+ frac{ pi }{6} )}=0$