Question

1) f(x)=3x^4 - 4x^3 - 36x^2 + 5

Answer 1

f(x)=3x⁴ - 4x³ - 36x² + 5
f''(x)=12x³-12x²-72x

Answer 2

f ' (x) = ( 3x^4 - 4x^3 - 36x^2 + 5) ' = 
= 3*(x^4) - 4*(x^3)' - 36*(x^2) ' + 5*(1)' =
= 3*4x^3 - 4*3x^2 - 36*2x + 5*0 =
= 12x^3 - 12x^2 - 72x = 
= 12x(x^2 - x - 6)