Question

Решить уравнение.
cos(2x-pi/2)=0

Answer 1

cos (2x - pi/2) = 0 
sin2x = 0 
2x = pik
x = pik/2, k ∈Z

Answer 2

$cos(2x-frac{pi}{2})=0;\ 2x-frac{pi}{2}=frac{pi}{2}+pi n, nin Z;\ 2x=fracpi2+fracpi2+pi n, nin Z;\ 2x=pi+pi n, nin Z; n+1=k, k,nin Z;\ 2x=pi k, kin Z;\ x=frac{pi k}{2}, kin Z$