Question

(3+b)^3+b(3+b)(2-b)-3b-b^2 разложите на множители

Answer 1

(3+b)³+b(3+b)(2-b)-3b-b²=(b+3)³+(-b³-b²+6b-b-b²)=(b+3)³+(-b³-2b²+3b)=
=(b+3)³-(b²-b)(b+3)=(b²+6b+9-b²+b)(b+3)=(7b+9)(b+3)