Question

(3х+5)*(4х-4)=(6х-3)*(2х+7)

Answer 1

$(3x+5)*(4x-4)=(6x-3)*(2x+7)\ 12x^2-12x+20x-20=12x^2+42x-6x-21\-12x+20x-42x+6x=-21+20\-28x=-1\x= frac{1}{28}$

Answer 2

12х+20х-20-12х=12х+42х-6х-21
-16х=-1
х=1/16