Question

sin^2 x - cos^2 x =1/2

Answer 1

$sin^2x-cos^2x=0,5 \ -(cos^2x-sin^2x)=0,5 \ cos2x=-0,5 \ 2x=pm frac{2 pi }{3} +2pi n,n in Z \ x=pm frac{pi}{3} +pi n,n in Z$

Answer 2

спасибо!

Answer 3

(1-cos^2x)-cos^2x = 1/2
1 - 2cos^2x = 1/2
-2cos^2x = -0,5
cos^2x = 0,25
cosx = +-0,5
cosx = 1/2
x = +-п/3 + 2пк к прин. z
x = -0,5
x = +-2п/3 + 2пн