Question

Решите систему уравнения

x^2=2y+3;
x^2+6=2y+y^2

Answer 1

x^2=2y+3;
x^2+6=2y+y^2
2y+3+6=2y+y^2
2y+9-2y-y^2=0
-y^2=-9
Y^2=9
Y=±3
x^2= 2*3+3=9
x=3
x^2=2*(-3)+3=-3
x ------нет
Ответ: (3;3), (3;-3)