Question

решите неравенство
2(х-1)-3(х+2)<6(1+х)
7(у+3)-2(у+2)≥2(5у+1)

Answer 1

Ответ:

2·(x–1)–3·(x+2)<6·(1+x)

2·x–2·1–3·x–3·2<6·1+6·x

2·x–2–3·x–6<6+6·x

2·x–3·x–6·x<6+2+6

–7·x<14       | :(–7)

x>14:(–7)

x>-2

x∈(-2; +∞)

7·(y+3)–2·(y+2)≥2·(5·y+1)

7·y+7·3–2·y–2·2≥2·5·y+2·1

7·y+21–2·y–4≥10·y+2

7·y–2·y–10·y≥2–21+4

–5·y≥–15        | :(–5)

y≤3

x∈(–∞; 3]