Question

Представьте в виде многочлена:
(y-4)(y+6)
(4a+1)(2a-3)
(2y-b)(4y+3b)
(a-3)(a2-5a+10)

Answer 1

(y-4)(y+6)=y²+2y-24
(4a+1)(2a-3)=8a²-10a-3
(2y-b)(4y+3b)=8y²+2by-3b²
(a-3)(a²-5a+10)=a³-8a²+25a-30

Answer 2

y²-24
8a²-3
8y²-3b²
2a²-5a²+10a-6a+15a-30=-3a²+19a-30