Question

Решите систему неравенств:

$\left \{ {{ \frac{x - 4}{8 } + \frac{x + 3}{6} men'she 7} \atop {(x - 3)^{2} men'she (x + 3) (x - 2) + 1 } \right.$

Answer 1

3x-12+4x+12<168⇒7x<168⇒x<24
x²-6x+9-x²+2x-3x+6-1<0⇒-7x<-14⇒x>2
x∈(2;24)