Question

№569
2,4
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Answer 1

$3arccos(-1)-2arccos0=3(\pi -arccos1)-2\cdot \frac{\pi}{2}=3(\pi -0)-\pi =2\pi \\\\4arccos(-\frac{\sqrt2}{2})+6arccos(-\frac{\sqrt3}{2})=4(\pi -\frac{\pi}{4})+6(\pi -\frac{\pi}{6})=4\pi-\pi+6\pi-\pi =8\pi$