Question

(4x-3)/(x+1) - 2/(1-x^2 ) = x/(x-1)

Answer 1

$frac{4х-3}{х+1} - frac{2}{1-х²}$ = $frac{х}{х-1}$
(1-х²)(5х-3)-2(х+1)=0
5х²-3х+5=0

Answer 2

$frac{4x-3}{x+1} - frac{2}{(1- x) ^{2} } = frac{x}{x-1}$