Question

HELP ME!
Надо вычислить.

Answer 1

пусть (29+4*7^0,5)^(1/6)=А
пусть (1+2*7^0,5)^(1/3)=((1+2*7^0,5)^2)^(1/6)=((1+2*7^0,5)^2)^(1/6)=В

(1+2*7^0,5)^2=1+2*1*2*7^0,5+4*7=29+4*7^0,5

В=((1+2*7^0,5)^2)^(1/6)=(29+4*7^0,5)^(1/6)=А

((29+4*7^0,5)^(1/6)-(1+2*7^0,5)^(1/3))*(231+12^(1/7))^(1/10)=
=(A-B)*(231+12^(1/7))^(1/10)= 0 *(231+12^(1/7))^(1/10) = 0 - это ответ

Answer 2

пусть (29+4*7^0,5)^(1/6)=А
пусть (1+2*7^0,5)^(1/3)=((1+2*7^0,5)^2)^(1/6)=((1+2*7^0,5)^2)^(1/6)=В

(1+2*7^0,5)^2=1+2*1*2*7^0,5+4*7=29+4*7^0,5

В=((1+2*7^0,5)^2)^(1/6)=(29+4*7^0,5)^(1/6)=А

((29+4*7^0,5)^(1/6)-(1+2*7^0,5)^(1/3))*(231+12^(1/7))^(1/10)=
=(A-B)*(231+12^(1/7))^(1/10)= 0 *(231+12^(1/7))^(1/10) = 0 - это ответ