Question

а) 5√2 + 23√27 - √98 б) (4√3 + √27) √3  в) ( √5- √3)во второй степени.

Answer 1

$5sqrt{2}+23sqrt{27}-sqrt{98}=6sqrt{2}+69sqrt{3}-7sqrt{2}=69sqrt{3}-sqrt{2} 4sqrt{3}+sqrt{27}=4sqrt{3}+3sqrt{3}=7sqrt{3}</var></p> <p><var> (sqrt{5}-sqrt{3})^2=5-2sqrt{15}+3=8-2sqrt{15}=2(4-sqrt{15})$

Answer 2

а)5√2+23√27-√98=5√2+69√3-7√2=-2√2+69√3

б)4√3*√3+√27*√3=√144+√81=√225=15

в)(√5-√3)^2=(√5)^2-2*√5*√3+(√3)^2=5-2√15+3=8-2√15=2(4-√15)