Question

Помогите,плиииз!!!!!!!!!!!
Очень нужно,не приходят идеи

Answer 1

(x³-3x²-9x+27)¹/²·(3-x)⁻¹=[x²(x-3)-9(x-3)]¹/²·(3-x)⁻¹=
=[(x²-9)(x-3)]¹/²·(3-x)⁻¹=[(x-3)(x+3)(x-3)]¹/²·(3-x)⁻¹=
=[(x-3)²(x+3)]¹/²·[-(x-3)]⁻¹=(x-3)(x+3)¹/²·(x-3)⁻¹=-(x-3)¹⁻¹·(x+3)¹/²=
=-(x+3)¹/²;
(x-18√(x-81))¹/² -(x+18√(x-81))¹/²=-6;⇒
[(x-18√(x-81))¹/²-(x+18√(x-81))¹/²]²=(-6)²;⇒
(x-18√(x-81)-2·(x-18√(x-81))¹/²·(x+18√(x-81))¹/²+(x+18√(x-81)=36;⇒
(2x-2·[x²-18²·(x-81)]¹/²=36;⇒
[x²-18²(x-81)]¹/²=-(36-2x)/2;⇒(x²-324x+26244)=(-18+x)²;⇒
x²-324x+26244=(324-36x+x²);⇒
x²-324x-x²+36x=324-26244;⇒-288x=-25920;⇒
x=25920/288=90