Question

помогите с математикой

Answer 1

д)3,2:(-0,4*0,2)=3,2:(-0,08)=-40
е)-4,9:(-0,2*0,3-0,1)=-4,9:(-0.06-0,1)=-4,9:(-0,16)=30,625
ж)$1 \frac{5}{12} :(- \frac{5}{6} + \frac{2}{3} )= \frac{17}{12} :(- \frac{5}{6}+ \frac{4}{6} )= \frac{17}{12} :(- \frac{1}{6} )= \frac{17}{12} *(- \frac{6}{1} )=- \frac{17}{2} =-8 \frac{1}{2}$
д)$(-0,2+ \frac{1}{3} ):3,2=(- \frac{1}{5} + \frac{1}{3} ): \frac{32}{10} =(- \frac{3}{15} + \frac{5}{15} ): \frac{16}{5} = \frac{2}{15} * \frac{5}{16} = \frac{1}{24}$