Question

Помогите пожалуйста

Answer 1

$\frac{a+3b}{b+3a}=[\frac{:b}{:b}]=\frac{\frac{a}{b}+3}{1+3\frac{a}{b}}=-8\\\\\frac{a}{b}+3=-8(1+3\frac{a}{b})\\\\\frac{a}{b}+3=-8-24\frac{a}{b}\\\\25\frac{a}{b}=-11\\\\\frac{a}{b}=-\frac{11}{25}$