Question

$\frac{ b^{ 5\sqrt{8} +1}}{ (b^{ \sqrt{8} }) ^{5} }$

при b=2

Answer 1

$\frac{b^{5 \sqrt{8}+1}}{b^{5 \sqrt{8}}}=b^{5 \sqrt{8}+1-5 \sqrt{8}}=b=2$