Question

решите уравнение))

(3-х)(х+2)=0

Answer 1

3x+6-x2-2x=O
-x2+x+6=O
x2-x-6=O
D= b2-4ac= 1-(4*(-6) ) = 1 + 24 = 25
x1= (1+5)/2=3
x2=(1-5)/2=-2

Answer 2

3-х₁=0
х₁=3
х₂+2=0
х₂=-2