Question

[tex] x^{2} +12x-28=0 как делать

Answer 1

$x^{2} +12x-28=0 D=( 144-4*1*(-28))= 144+112=256 x_{1} = (-12+16)/2= 2 x_{2} = (-12-16)/2= -14$

Ответ: x₁=2 ; x₂= -14   .