Question

преобразуйте в произведение
1-6а+9а^=?

Answer 1

$9a^{2} - 6a + 1 = 0 \\ a_{1,2} = \frac{1}{3} \\ 9a^{2} - 6a + 1 = 9(a - \frac{1}{3})*(a - \frac{1}{3}) = (3a - 1)(3a - 1)$