Question

(4а@3- 4 а в третьей степени) 7 Класс: (4а@3+5)@2+(4а@3-1)@2-2 *(4а@3+5)(4а@3-1)

Answer 1

(4а^3+5)^2+(4а^3-1)^2-2 *(4а^3+5)(4а^3-1)=(4а^3+5)^2-2 *(4а^3+5)(4а^3-1)+(4а^3-1)^2=((4а^3+5)-(4а^3-1))^2=(4а^3+5-4а^3+1)^2=6^2=36