Question

3х2(2х-1)+х(2х-1)+2(1-2х)=0

Answer 1

3x^2(2x-1)+x(2x-1)+2(1-2x)=0
3x^2(2x-1)+x(2x-1)-2(2x-1)=0
(2x-1)(3x^2+x-2)=0
2x-1=0
x_1 = 0.5
3x^2 + x - 2 = 0
D = 1^2 - 4*3*(-2) = 1 + 24 = 25
√25 = 5
x_2 =(-1+5)/6 = 4/6 = 2/3
x_3 = (-1-5)/6 = -6/6 = -1
Ответ: x_1 = 0.5 ; x_2 = 2/3 ; x_3 = -1