Question

помоги те пожже............

Answer 1

$(\frac{1}{m-1}- \frac{m+1}{m^2+m+1}):(1+ \frac{1}{m^3-1})= \frac{m^2+m+1-m^2+1}{(m-1)(m^2+m+1)}: \frac{m^3-1+1}{m^3-1}= \\ = \frac{m+2}{m^3-1}* \frac{m^3-1}{m^3}= \frac{m+2}{m^3}$

Answer 2

$( \frac{1}{m-1} - \frac{m+1}{m^{2}+ m+1}):(1+ \frac{1}{m^{3}-1} )= \\ = ( \frac{m^{2}+ m+1}{(m-1)(m^{2}+ m+1)} - \frac{(m+1)(m-1)}{(m-1)(m^{2}+ m+1)}):(1+ \frac{1}{m^{3}-1} )= \\ =\frac{m^{2}+ m+1-m^{2}+1}{(m-1)(m^{2}+ m+1)} :\frac{m^{3}-1+1}{m^{3}-1} = \\ =\frac{m+2}{m^{3}-1} * \frac{m^{3}-1}{m^{3}} =\frac{m+2}{m^{3}}$