Question

Помогите!Решить:

4- 3a/ 5-2b + 5(a-10)/ 2b-5

Answer 1

$4-\frac{3a}{5-2b}+ \frac{5(a-10)}{2b-5}= \frac{20-8b}{5-2b}-\frac{3a}{5-2b}-\frac{5a-50}{5-2b}= \frac{20-8b-3a-5a+50}{5-2b}= \\ =\frac{70-8a-8b}{5-2b}=-\frac{70-8a-8b}{2b-5}=\frac{8a+8b-70}{2b-5}$