Question

(3 целых 5 /6 )-2 целых 1 шестых =5

Answer 1

$(3 \frac{5}{6}+a) -2 \frac{1}{6}=5$
$(3 \frac{5}{6}+a) =5+2 \frac{1}{6} \\ \\ (3 \frac{5}{6}+a) =7 \frac{1}{6} \\ \\ a=7 \frac{1}{6} -3 \frac{5}{6} \\ \\ a=6 \frac{7}{6}-3 \frac{5}{6} \\ \\ a=3 \frac{2}{6}$
$a=3 \frac{1}{3}$