Question

Найти массовую долю каждого элемента:Ca(OH)₂,Fe₂(SO₄)₃

Answer 1

Ca= 40÷74×100=54.05
O=16÷74×100=21.6
H=1÷74×100=1.3

Answer 2

1) W(Ca) = Ar(Ca) * n / M (Ca(OH)2) *100% = 40 *1 / 74 *100% = 54%

    W(O) = Ar(O) *n / М(Са(ОН)2 *100% = 16 *2 / 74 * 100% = 43%

    W(H) = Ar(H) * n / М(Са(ОН)2) *100% = 1 *2 / 74 * 100 % = 2,7%

2) W(Fe) = Ar(Fe) * n / М(Fe2(SO4)3) * 100% = 56 * 2 / 300 * 100% = 37%

W(S) = Ar(S) * n / М(Fe2(SO4)3 * 100% = 32 * 3 / 300 *100% = 32%

W(O) = Ar(O) * n / М(Fe2(SO4)3 * 100% = 16 * 12 / 300 * 100% = 64%