Question

решение уравнения и письменно проверить

Answer 1

$\frac{4x+8}5-\frac{5x-3}4=\frac{7x-1}{20}\\\frac{4(4x+8)-5(5x-3)}{20}=\frac{7x-1}{20}\\16x+32-25x+15=7x-1\\16x-25x-7x=-1-32-15\\-16x=-48\\x=3\\\\\Pi POBEPKA:\\\frac{4\cdot3+8}5-\frac{5\cdot3-3}4=\frac{12+8}5-\frac{15-3}4=\frac{20}5-\frac{12}4=4-3=1\\\frac{7\cdot3-1}{20}=\frac{21-1}{20}=\frac{20}{20}=1\\1=1$