Question

$\frac{(3x-1) ^{2} }{3}= (3x-4)(x+2)$

Answer 1

$\frac{(3x-1)^{2}}{3} =(3x-4)(x+2) |*3\\ (3x-1)^{2}=3(3x-4)(x+2)\\ 9x^{2}-6x+1=3(3x^{2}+6x-4x-8)\\ 9x^{2}-6x+1=9x^{2}+6x-24\\ -6x-6x=-24-1 \\ -12x=-25 \\ x= \frac{25}{12}$